Inverse Trig Calculator
Find angles from trig values using arcsin, arccos, and arctan. Get principal values in degrees and radians, all-quadrant solutions, domain/range rules, derivative formulas, and the identity arcsin(x) + arccos(x) = π/2.
Angle (degrees)
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Angle (radians) —
Principal value range —
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Angle (degrees)
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Angle (radians) —
Principal range —
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All Inverse Values
arcsin, arccos, arctan values —
Identity: arcsin(x) + arccos(x) —
Calculus & Domains
Derivative formulas —
Domain & range summary —
How to Use This Calculator
- Enter the trig value and select the inverse function (arcsin, arccos, or arctan).
- The angle is returned in both degrees and radians.
- Use All Quadrants to find all solutions in 0°–360°.
- Use From Side Ratios to compute angles from triangle side lengths.
Formula
arcsin(x) → angle θ such that sin(θ) = x, θ ∈ [−90°, 90°]
arccos(x) → θ such that cos(θ) = x, θ ∈ [0°, 180°]
arctan(x) → θ such that tan(θ) = x, θ ∈ (−90°, 90°)
Example
arcsin(0.5) = 30° | arccos(0.5) = 60° | arctan(1) = 45° | arcsin(0.5) + arccos(0.5) = 90° = π/2 ✓
Frequently Asked Questions
- arcsin(x) is the inverse sine function — it returns the angle θ such that sin(θ) = x. The principal value range is [−90°, 90°] (or [−π/2, π/2] in radians), and the domain is [−1, 1]. For example, arcsin(0.5) = 30° because sin(30°) = 0.5. arcsin(1) = 90°, arcsin(0) = 0°, arcsin(−1) = −90°. If |x| > 1, arcsin is undefined in real numbers (no real angle has a sine greater than 1). The principal range ensures each input has exactly one output.
- arccos(x) returns angles in [0°, 180°] (or [0, π] radians). This range ensures one unique output per input (making arccos a true function). The domain is [−1, 1]. For example: arccos(1) = 0°, arccos(0) = 90°, arccos(−1) = 180°. Note that arccos and arcsin are complementary: arcsin(x) + arccos(x) = 90° = π/2 for all x in [−1, 1]. So arccos(0.5) = 60° (since arcsin(0.5) = 30° and 30 + 60 = 90).
- Because sin(30°) = 0.5, and arcsin is the inverse: arcsin(0.5) = 30° = π/6 radians. The arcsin function asks: "what angle has a sine of 0.5?" Only within the principal range [−90°, 90°] does 30° uniquely answer this. Note that 150° also has sin(150°) = 0.5, but 150° falls outside the principal range [−90°, 90°], so arcsin returns 30°, not 150°. To find all solutions to sin(θ) = 0.5, use: θ = 30° + 360°n or θ = 150° + 360°n.
- For any x in [−1, 1], arcsin(x) and arccos(x) are complementary angles that always sum to π/2 radians (90°). This follows from the co-function identity: sin(θ) = cos(90° − θ). If arcsin(x) = θ, then sin(θ) = x, so cos(90°−θ) = x, meaning arccos(x) = 90° − θ. Therefore arcsin(x) + arccos(x) = θ + (90°−θ) = 90°. Example: arcsin(0.6) + arccos(0.6) ≈ 36.87° + 53.13° = 90°. ✓ This identity is useful for simplifying expressions and checking calculator results.
- arctan(x) is the inverse tangent function — it returns the angle θ such that tan(θ) = x. Unlike arcsin and arccos, arctan is defined for all real x (the entire number line), and returns values in (−90°, 90°) (open interval, excluding the endpoints because tan is undefined there). Examples: arctan(1) = 45°, arctan(0) = 0°, arctan(−1) = −45°, arctan(√3) = 60°. As x → ∞, arctan(x) → 90°; as x → −∞, arctan(x) → −90°. arctan is used to find angles from slope ratios (opposite/adjacent) in right triangles.
Related Calculators
Sources & References (5) ▾
- Calculus — James Stewart, Chapter 1 — Cengage Learning
- OpenStax Algebra and Trigonometry — Chapter 8 — OpenStax
- MIT OpenCourseWare 18.01 — Trigonometric Functions — MIT OCW
- Khan Academy — Inverse Trig Functions — Khan Academy
- NIST DLMF Chapter 4 — Inverse Trigonometric Functions — NIST